Understanding the meaning of lvalues and rvalues in C++

Lvalues and rvalues: a friendly definition

In C++ an lvalue is something that points to a specific memory location.

A rvalue is something that doesn't point to anywhere.

In general, rvalues are temporary and short lived, while lvalues live a longer life since they exist as variables. It's also fun to think of lvalues as containers and rvalue as things contained in the container.

int x = 666;

Here 666 is an rvalue; a number (technically a literal constant) has no specific memory address, except for some temporary register while the program is running. That number is assigned to x, which is a variable. A variable has a specific memory location, so its an lvalue. C++ states that an assignment requires an lvalue as its left operand: this is perfectly legal;.

int* y = &x;

Here I'm grabbing the memory address of x and putting it into y, through the address-of operator &. It takes an lvalue argument and produces an rvalue. This is another perfectly legal operation: on the left side of the assignment we have an lvalue (a variable), on the right side an rvalue produced by the address-of operator.

int y;
666 = y; //error!

The technical reason is that 666, being a literal constant - so an rvalue, doesn't have a specific memory location. y is assigned nowhere.

int* y = &666; // error

The & operator wants an lvalue in input, because only an lvalue has an address that & can process.

Functions returning lvalues and rvalues

Left operand of an assignment must be an lvalue.

int setValue(){
    return 6;
}

setValue() = 3; // error

setValue() returns an rvalue (the temporary number 6), which cannot be a left operand of assignment.

int global = 100;

int& setGlobal(){
    return global;
}

setGlobal = 400;    // ok

It works because setGlobal returns a reference.

Lvalue to rvalue conversion

An lvalue may get converted to an rvalue. According to the C++ specification, it takes two rvalues as arguments and return an rvalue.

int x = 1;
int y = 3;
int z = x + y;

x and y have undergone an implicit lvalue-to-rvalue conversion

Lvalue references

int y = 10
int& yref = y;
yref++;         // y is now 11

yref is of type int&: a reference to y. It's called an lvalue reference

void fnc(int& x){

}

int main(){
    fuc(10);    // error
    int x = 10;
    fnc(x);     // ok
}

Const lvalue reference to the rescue

You are allowed to bind a const lvalue to an rvalue

// this
const int& ref = 10;    // OK!

// would translate to
int __internal_unique_name = 10;
const int& ref = __internal_unique_name;

void fnc(const int& x){

}

int main(){
    fnc(10);    // ok
}

References: https://www.internalpointers.com/post/understanding-meaning-lvalues-and-rvalues-c